4=2x^2-5

Solution for 4=2x^2-5 equation:

4=2x^2-5

We move all terms to the left:

4-(2x^2-5)=0

We get rid of parentheses

-2x^2+5+4=0

We add all the numbers together, and all the variables

-2x^2+9=0

a = -2; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-2)·9
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*-2}=\frac{0-6\sqrt{2}}{-4}
=-\frac{6\sqrt{2}}{-4}
=-\frac{3\sqrt{2}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*-2}=\frac{0+6\sqrt{2}}{-4}
=\frac{6\sqrt{2}}{-4}
=\frac{3\sqrt{2}}{-2}
$